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Showing posts with label UN LOGARITMA DAN EKSPONENSIAL. Show all posts
Showing posts with label UN LOGARITMA DAN EKSPONENSIAL. Show all posts

Monday, March 18, 2019

Pembahasan Soal UN Materi Logaritma

Konsep dasar yang digunakan dalam perhitungan:
  • $^{a}log\ b+^{a}log\ c=^{a}log\ b.c$
  • $^{a}log\ b-^{a}log\ c=^{a}log\ \left ( \frac{b}{c} \right )$
  • $^{a}log\ b\ ^{b}log\ c=^{a}log\ c$
  • $^{a^{n}}log\ b^{m}=\frac{m}{n}\ ^{a}log\ b$

Soal 1. UN SMA Tapel 2014/2015 Program Studi IPA
Hasil $\frac{^{7}log\ 16\sqrt{2}\ ^{2\sqrt{2}}log\ \frac{1}{49}+^{2}log\ \frac{1}{16}}{^{5}log\ 5\sqrt{5}+^{2}log\ 25\sqrt{5}}$ adalah ...
A. $10$
B. $\frac{5}{2}$
C. $\frac{-7}{2}$
D. $\frac{-5}{2}$
E. $-10$
Pembahasan
$\frac{^{7}log\ 16\sqrt{2}\ ^{2\sqrt{2}}log\ \frac{1}{49}+^{2}log\ \frac{1}{16}}{^{5}log\ 5\sqrt{5}+^{2}log\ 25\sqrt{5}}$
$=\frac{^{7}log\ 2^{4}.2^{\frac{1}{2}}\ ^{2.2^{\frac{1}{2}}}log\ 7^{-2}+^{2}log\ 2^{-4}}{^{5}log\ 125.5}$
$=\frac{^{7}log\ 2^{\frac{9}{2}}\ ^{2^{\frac{3}{2}}}log\ 7^{-2}+^{2}log\ 2^{-4}}{^{5}log\ 5^{4}}$
$=\frac{\left ( \frac{9}{2} \right )\left ( \frac{1}{\frac{3}{2}} \right )(-2)\ ^{7}log\ 2\ ^{2}log\ 7+(-4)\ ^{2}log\ 2}{4\ ^{5}log\ 5}$
$=\frac{(3)(-2)\ ^{7}log\ 7+(-4).1}{4.1}$
$=\frac{(-6)+(-4)}{4}$
$=\frac{(-10)}{4}$
$=\frac{-5}{2}$
Jawaban D

Soal 2. UN SMA Tapel 2016/2017 Program Studi IPS
Hasil dari $^{7} log 4.\ ^{2} log 5+ ^{7}log \frac{49}{25}=$ ...
A. $1$
B. $2$
C. $3$
D. $4$
E. $5$
Pembahasan
$^{7} log 4.\ ^{2} log 5+ ^{7}log \frac{49}{25}$
$= ^{7} log 2^{2}.\ ^{2} log 5+ ^{7}log \frac{7^{2}}{5^{2}}$
$= 2.\ ^{7} log 2.\ ^{2} log 5+ ^{7}log \left (\frac{7}{5} \right )^{2}$
$= 2.\ ^{7} log 5+ 2.\ ^{7}log \left (\frac{7}{5} \right )$
$= 2. \left ( ^{7} log 5+\ ^{7}log \left (\frac{7}{5} \right ) \right )$
$= 2.\ ^{7} log\ 5.\frac{7}{5}$
$= 2.\ ^{7} log\ 7=2$
Jawaban B

Soal 3. UN SMA Tapel 2016/2017 Program Studi IPA
Hasil $\frac{^{\sqrt{3}} log\ 5\ ^{25} log\ 3\sqrt{3}-^{4} log\ 16}{^{3} log\ 54-^{3} log\ 2}$ adalah ...
A. $-\frac{9}{2}$
B. $-\frac{1}{6}$
C. $-\frac{1}{3}$
D. $3$
E. $\frac{9}{2}$
Pembahasan
$\frac{^{\sqrt{3}} log\ 5\ ^{25} log\ 3\sqrt{3}-^{4} log\ 16}{^{3} log\ 54-^{3} log\ 2}$
$=\frac{^{3^{\left ( \frac{1}{2} \right )}} log\ 5\ ^{5^{5}} log\ 3^{\left ( \frac{3}{2} \right )}-^{4} log\ 4^{2}}{^{3} log\ \frac{54}{2}}$
$=\frac{\frac{1}{\frac{1}{2}}.\frac{1}{2}.\frac{3}{2}\ ^{3} log\ 5\ ^{5} log\ 3-2.\ ^{4} log\ 4}{^{3} log\ 27}$
$=\frac{\frac{3}{2}\ ^{3} log\ 3-2.1}{^{3} log\ 3^{3}}$
$=\frac{\frac{3}{2}\ ^{3} log\ 3-2.1}{3.\ ^{3} log\ 3}$
$=\frac{\frac{3}{2}.1-2.1}{3.1}$
$=\frac{\frac{3}{2}-2}{3}$
$=-\frac{1}{6}$
Jawaban B